Verified Solution • 2025–26 Session moderate

QJEEM24Phc793: JEE Main 2024 Physics - Class 12 JEEM24Phc793 Solution: If the total energy transferred to a surface in time is , then…

If the total energy transferred to a surface in time t\mathrm{t} is 6.48×105 J6.48 \times 10^5 \mathrm{~J} , then the magnitude of the total momentum delivered to this surface for complete absorption will be:

Multiple Choice Options

  • A 2.16×10−3 kg m/s2.16 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}
  • B 2.46×10−3 kg m/s2.46 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}
  • C 1.58×10−3 kg m/s1.58 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}
  • D 4.32×10−3 kg m/s4.32 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}

Step-by-Step Verified Solution

p=EC=6.48×1053×108=2.16×10−3\mathrm{p=\frac{E}{C}=\frac{6.48 \times 10^5}{3 \times 10^8}=2.16 \times 10^{-3}}

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring