QJEEM24Phc61b: JEE Main 2024 Physics - Class 11 JEEM24Phc61b Solution: If the radius of curvature of the path of two particles of same …

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QJEEM24Phc61b: JEE Main 2024 Physics - Class 11 JEEM24Phc61b Solution: If the radius of curvature of the path of two particles of same …

If the radius of curvature of the path of two particles of same mass are in the ratio $3 : 4$ , then in order to have constant centripetal force, their velocities will be in the ratio of :

Multiple Choice Options

A 1:03
B 2:03
C 3:02
D 3:01

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Accepted Answer

Given $m_{1} = m_{2}$

$and \frac{r_{1}}{r_{2}} = \frac{3}{4}$

As centripetal force $F = \frac{{mv}^{2}}{r}$

In order to have constant (same in this question) centripetal force

$\begin{aligned} F_{1} = F_{2} \\ \frac{m_{1} v_{1}^{2}}{r_{1}} = \frac{m_{2} v_{2}^{2}}{r_{2}} \\ \Rightarrow \frac{v_{1}}{v_{2}} = \sqrt{\frac{r_{1}}{r_{2}}} = \frac{\sqrt{3}}{2} \end{aligned}$

QJEEM24Phc61b: JEE Main 2024 Physics - Class 11 JEEM24Phc61b Solution: If the radius of curvature of the path of two particles of same …

Multiple Choice Options

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