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QJEEM24Phb7a8: JEE Main 2024 Physics - Class 12 JEEM24Phb7a8 Solution: Match List I with List II .tg…

Match List I with List II

List I List II
(A) Gauss's law of magnetostatics (I) ∮E⃗⋅d⃗a=1ε0∫ρdV\oint \vec{E} \cdot \vec{d} a=\frac{1}{\varepsilon_0} \int \rho d V
(B) Faraday's law of electro magnetic induction (II) ∮B⃗⋅d⃗a=0\oint \vec{B} \cdot \vec{d} a=0
(C) Ampere's law (III) ∫E⃗⋅d⃗l=−ddt∫B⃗⋅d⃗a\int \vec{E} \cdot \vec{d} l=\frac{-d}{d t} \int \vec{B} \cdot \vec{d} a
(D) Gauss's law of electrostatics (IV) ∮B⃗⋅d⃗l=μ0I\oint \vec{B} \cdot \vec{d} l=\mu_0 I

Choose the correct answer from the options given below:

Multiple Choice Options

  • A A-III, B-IV, C-I, D-II
  • B A-IV, B-II, C-III, D-I
  • C A-II, B-III, C-IV, D-I
  • D A-I, B-III, C-IV, D-II

Step-by-Step Verified Solution

Let's identify each law listed in List I and match it with the corresponding mathematical expression listed in List II.

Gauss's law of magnetostatics states that the total magnetic flux through a closed surface is zero, as magnetic monopoles do not exist. This is given by the formula:

∮B⃗⋅da⃗=0\oint \vec{B} \cdot \vec{da} = 0

So, (A) matches with (II).

Faraday's law of electromagnetic induction states that the induced electromotive force (emf) in any closed loop is equal to the negative of the time rate of change of the magnetic flux through the loop. It is given by:

∮E⃗⋅dl⃗=−ddt∫B⃗⋅da⃗\oint \vec{E} \cdot \vec{dl} = -\frac{d}{dt} \int \vec{B} \cdot \vec{da}

Hence, (B) matches with (III).

Ampere's law relates the integrated magnetic field around a closed loop to the electric current passing through the loop. The mathematical expression given in the context of magnetostatics (without the displacement current) is:

∮B⃗⋅dl⃗=μ0I\oint \vec{B} \cdot \vec{dl} = \mu_0 I

Consequently, (C) matches with (IV).

Lastly, Gauss's law of electrostatics states that the total electric flux out of a closed surface is proportional to the charge enclosed within the surface:

∮E⃗⋅da⃗=1ε0∫ρdV\oint \vec{E} \cdot \vec{da} = \frac{1}{\varepsilon_0} \int \rho dV

Therefore, (D) matches with (I).

Based on these matches, the correct answer must link A-II, B-III, C-IV, and D-I:

The correct option is:

Option C

A-II, B-III, C-IV, D-I

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