QJEEM24Phb78a: JEE Main 2024 Physics - Class 11 JEEM24Phb78a Solution: A body of mass ' m ' is projected with a speed ' u ' making an…

A body of mass '$$m$$' is projected with a speed '$$u$$' making an angle of $${45}^{\circ }$$ with the ground. The angular momentum of the body about the point of projection, at the highest point is expressed as $$\frac{\sqrt{2}m{u}^3}{Xg}$$. The value of '$$X$$' is _________.