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QJEEM24Phb767: JEE Main 2024 Physics - Class 12 JEEM24Phb767 Solution: In an experiment to measure focal length ( ) of convex lens,…

In an experiment to measure focal length ( ff ) of convex lens, the least counts of the measuring scales for the position of object (u) and for the position of image (v) are Δu\Delta u and Δv\Delta v , respectively. The error in the measurement of the focal length of the convex lens will be:

Multiple Choice Options

  • A 2f[Δuu+Δvv]2 f\left[\frac{\Delta \mathrm{u}}{\mathrm{u}}+\frac{\Delta \mathrm{v}}{\mathrm{v}}\right]
  • B f[Δuu+Δvv]f\left[\frac{\Delta \mathrm{u}}{\mathrm{u}}+\frac{\Delta \mathrm{v}}{\mathrm{v}}\right]
  • C f2[Δuu2+Δvv2]f^2\left[\frac{\Delta \mathrm{u}}{\mathrm{u}^2}+\frac{\Delta \mathrm{v}}{\mathrm{v}^2}\right]
  • D Δuu+Δvv\frac{\Delta \mathrm{u}}{\mathrm{u}}+\frac{\Delta \mathrm{v}}{\mathrm{v}}

Step-by-Step Verified Solution

First, let's understand the relationship between the object distance ( uu ), the image distance ( vv ), and the focal length ( ff ) of a convex lens, which is given by the lens formula:

1f=1v+1u\frac{1}{f} = \frac{1}{v} + \frac{1}{u}

Now, to find the error in the focal length ( Δf\Delta f ) due to the errors in the measurements of uu and vv ( Δu\Delta u and Δv\Delta v , respectively), we have to differentiate the lens formula with respect to uu and vv , keeping in mind the propagation of error.

By differentiating both sides of the lens formula with respect to vv and uu , and also considering the negative reciprocal relation (given ff is a constant for a specific lens), we have:

Δff2=Δvv2+Δuu2\frac{\Delta f}{f^2} = \frac{\Delta v}{v^2} + \frac{\Delta u}{u^2}

Rearranging this equation to find Δf\Delta f , we get:

Δf=f2(Δvv2+Δuu2)\Delta f = f^2 \left( \frac{\Delta v}{v^2} + \frac{\Delta u}{u^2} \right)

Therefore, the correct option showing the error in the measurement of the focal length of the convex lens, taking into account the least counts ( Δu\Delta u and Δv\Delta v ) of the measuring scales for the position of the object ( uu ) and for the position of the image ( vv ), is:

Option C: f2[Δuu2+Δvv2]f^2\left[\frac{\Delta \mathrm{u}}{\mathrm{u}^2}+\frac{\Delta \mathrm{v}}{\mathrm{v}^2}\right]

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