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QJEEM24Phb5cf: JEE Main 2024 Physics - Class 11 JEEM24Phb5cf Solution: A block is simply released from the top of an inclined plane as …

JEE Main 2024 (Online) 8th April Evening Shift Physics - Work Power & Energy Question 16 English

A block is simply released from the top of an inclined plane as shown in the figure above. The maximum compression in the spring when the block hits the spring is :

Multiple Choice Options

  • A 6 m\sqrt{6} \mathrm{~m}
  • B 5 m\sqrt{5} \mathrm{~m}
  • C 1 m1 \mathrm{~m}
  • D 2 m2 \mathrm{~m}

Step-by-Step Verified Solution

amp;Wg+WFr+Ws=ΔKEamp;5×10×5−0.5×5×10×x−12Kx2=0−0amp;250=25x+50x2amp;2x2+x−10=0amp;x=2\begin{aligned} & \mathrm{W}_{\mathrm{g}}+\mathrm{W}_{\mathrm{Fr}}+\mathrm{W}_{\mathrm{s}}=\Delta \mathrm{KE} \\\\ & 5 \times 10 \times 5-0.5 \times 5 \times 10 \times \mathrm{x}-\frac{1}{2} \mathrm{Kx}^2=0-0 \\\\ & 250=25 \mathrm{x}+50 \mathrm{x}^2 \\\\ & 2 \mathrm{x}^2+\mathrm{x}-10=0 \\\\ & \mathrm{x}=2\end{aligned}

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