QJEEM24Phafc9: JEE Main 2024 Physics - Class 12 JEEM24Phafc9 Solution: When a voltage of is applied to an inductor, a current of flows …

To determine the power dissipated in the circuit, follow these steps:

1. Calculate the resistance (R) using the DC current:

$R = \frac{100 \, \text{V}}{5 \, \text{A}} = 20 \, \Omega$

1. Determine the impedance (Z) by considering both resistance (R) and inductive reactance ( $X_L$ ):

$Z = \sqrt{R^2 + X_L^2} = \sqrt{20^2 + (20\sqrt{3})^2} = 40 \, \Omega$

1. Compute the peak current ( $I_0$ ) using the AC peak voltage ( $V_0$ ):

$I_0 = \frac{V_0}{Z} = \frac{200 \, \text{V}}{40 \, \Omega} = 5 \, \text{A}$

1. Calculate the power (P) using the RMS values of voltage and current, and consider the phase angle ( $\cos \phi$ ):

$P = V_{\text{rms}} \cdot I_{\text{rms}} \cdot \cos \phi = \frac{V_0 \cdot I_0}{2} \times \frac{R}{Z} = \frac{200 \cdot 5}{2} \times \frac{20}{40} = 250 \, \text{W}$