QJEEM24Phabc5: JEE Main 2024 Physics - Class 12 JEEM24Phabc5 Solution: Two charges q and 3 q are separated by a distance ' r ' in air. …

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QJEEM24Phabc5: JEE Main 2024 Physics - Class 12 JEEM24Phabc5 Solution: Two charges q and 3 q are separated by a distance ' r ' in air. …

Two charges $q$ and $3 q$ are separated by a distance ' $r$ ' in air. At a distance $x$ from charge $q$ , the resultant electric field is zero. The value of $x$ is :

Multiple Choice Options

A r3(1+3)
B (1+3)r
C r(1+3)
D r(1+3)

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Accepted Answer

JEE Main 2024 (Online) 31st January Morning Shift Physics - Electrostatics Question 40 English Explanation

$\begin{aligned} {({\vec{E}}_{net})}_{P} = 0 \\ \frac{kq}{x^{2}} = \frac{k \cdot 3 q}{(r - x)^{2}} \\ (r - x)^{2} = 3 x^{2} \\ r - x = \sqrt{3} x \\ x = \frac{r}{\sqrt{3} + 1} \end{aligned}$

QJEEM24Phabc5: JEE Main 2024 Physics - Class 12 JEEM24Phabc5 Solution: Two charges q and 3 q are separated by a distance ' r ' in air. …

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