Verified Solution • 2025–26 Session moderate

QJEEM24Phaad2: JEE Main 2024 Physics - Class 12 JEEM24Phaad2 Solution: An electric toaster has resistance of at room temperature . The …

An electric toaster has resistance of 60Ω60 \Omega at room temperature (27∘C)\left(27^{\circ} \mathrm{C}\right) . The toaster is connected to a 220 V220 \mathrm{~V} supply. If the current flowing through it reaches 2.75 A2.75 \mathrm{~A} , the temperature attained by toaster is around : ( if α=2×10−4\alpha=2 \times 10^{-4} / ∘C^\circ \mathrm{C} )

Multiple Choice Options

  • A 1235 ∘^\circ C
  • B 1667 ∘^\circ C
  • C 694 ∘^\circ C
  • D 1694 ∘^\circ C

Step-by-Step Verified Solution

amp;RT−27=60Ω,RT=2202.75=80Ωamp;R=R0(1+αΔT)amp;80=60[1+2×10−4( T−27)]amp;T≈1694∘C\begin{aligned}& \mathrm{R}_{\mathrm{T}-27}=60 \Omega, R_T=\frac{220}{2.75}=80 \Omega \\& \mathrm{R}=\mathrm{R}_0(1+\alpha \Delta \mathrm{T}) \\& 80=60\left[1+2 \times 10^{-4}(\mathrm{~T}-27)\right] \\& \mathrm{T} \approx 1694^{\circ} \mathrm{C}\end{aligned}

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