QJEEM24Pha90b: JEE Main 2024 Physics - Class 11 JEEM24Pha90b Solution: When the displacement of a simple harmonic oscillator is one…

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QJEEM24Pha90b: JEE Main 2024 Physics - Class 11 JEEM24Pha90b Solution: When the displacement of a simple harmonic oscillator is one…

When the displacement of a simple harmonic oscillator is one third of its amplitude, the ratio of total energy to the kinetic energy is $\frac{x}{8}$ , where $x =$ _________.

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$\begin{aligned} Let total energy = E = \frac{1}{2} {KA}^{2} \\ U = \frac{1}{2} K {(\frac{A}{3})}^{2} = \frac{{KA}^{2}}{2 \times 9} = \frac{E}{9} \\ KE = E - \frac{E}{9} = \frac{8 E}{9} \\ Ratio \frac{Total}{KE} = \frac{E}{\frac{8 E}{9}} = \frac{9}{8} \\ x = 9 \end{aligned}$

QJEEM24Pha90b: JEE Main 2024 Physics - Class 11 JEEM24Pha90b Solution: When the displacement of a simple harmonic oscillator is one…

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