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QJEEM24Pha87c: JEE Main 2024 Physics - Class 12 JEEM24Pha87c Solution: The ratio of the magnitude of the kinetic energy to the…

The ratio of the magnitude of the kinetic energy to the potential energy of an electron in the 5th excited state of a hydrogen atom is :

Multiple Choice Options

  • A 4
  • B 1
  • C 12\frac{1}{2}
  • D 14\frac{1}{4}

Step-by-Step Verified Solution

12∣PE∣=KE\frac{1}{2}|P E|=K E for each value of n\mathrm{n} (orbit)

∴KE∣PE∣=12\therefore \frac{K E}{|P E|}=\frac{1}{2}

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