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QJEEM24Pha502: JEE Main 2024 Physics - Class 12 JEEM24Pha502 Solution: An ac source is connected in given series LCR circuit. The rms…

An ac source is connected in given series LCR circuit. The rms potential difference across the capacitor of 20μF20 \mu \mathrm{F} is __________ V.

JEE Main 2024 (Online) 5th April Morning Shift Physics - Alternating Current Question 8 English

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amp;(Vrms)c=VrmsZXcamp;=50(500−100)2+3002×500amp;=50 V\begin{aligned}& \left(V_{r m s}\right)_c=\frac{V_{r m s}}{Z} X_c \\& =\frac{50}{\sqrt{(500-100)^2+300^2}} \times 500 \\& =50 \mathrm{~V}\end{aligned}

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