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QJEEM24Pha464: JEE Main 2024 Physics - Class 11 JEEM24Pha464 Solution: A light string passing over a smooth light fixed pulley…

A light string passing over a smooth light fixed pulley connects two blocks of masses m1m_1 and m2m_2 . If the acceleration of the system is g/8g / 8 , then the ratio of masses is:

JEE Main 2024 (Online) 31st January Evening Shift Physics - Laws of Motion Question 21 English

Multiple Choice Options

  • A 81\frac{8}{1}
  • B 97\frac{9}{7}
  • C 53\frac{5}{3}
  • D 43\frac{4}{3}

Step-by-Step Verified Solution

amp;a=(m1−m2)g(m1+m2)=g8amp;8m1−8m2=m1+m2amp;7m1=9m2amp;m1m2=97\begin{aligned}& a=\frac{\left(m_1-m_2\right) g}{\left(m_1+m_2\right)}=\frac{g}{8} \\& 8 m_1-8 m_2=m_1+m_2 \\& 7 m_1=9 m_2 \\& \frac{m_1}{m_2}=\frac{9}{7}\end{aligned}

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