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QJEEM24Pha183: JEE Main 2024 Physics - Class 12 JEEM24Pha183 Solution: The mass defect in a particular reaction is . The amount of…

The mass defect in a particular reaction is 0.4 g0.4 \mathrm{~g} . The amount of energy liberated is n×107 kWhn \times 10^7 \mathrm{~kWh} , where n=n= __________. (speed of light =3×108 m/s)\left.=3 \times 10^8 \mathrm{~m} / \mathrm{s}\right)

Step-by-Step Verified Solution

amp;E=Δmc2amp;=0.4×10−3×(3×108)2amp;=3600×107kWsamp;=3600×1073600kWh=1×107kWh\begin{aligned}& \mathrm{E}=\Delta \mathrm{mc}^2 \\& =0.4 \times 10^{-3} \times\left(3 \times 10^8\right)^2 \\& =3600 \times 10^7 \mathrm{kWs} \\& =\frac{3600 \times 10^7}{3600} \mathrm{kWh}=1 \times 10^7 \mathrm{kWh}\end{aligned}

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