QJEEM24Ph9d34: JEE Main 2024 Physics - Class 12 JEEM24Ph9d34 Solution: In the given circuit if the power rating of Zener diode is ,…

Question

Verified Solution • 2025–26 Session moderate

In the given circuit if the power rating of Zener diode is

10 \mathrm{~mW}

, the value of series resistance

R_s

to regulate the input unregulated supply is :

JEE Main 2024 (Online) 1st February Morning Shift Physics - Semiconductor Question 30 English

Accepted Answer

Pd across

R_s

V_{1} = 8 - 5 = 3 V

Current through the load resistor

I = \frac{5}{1 \times 10^{3}} = 5 mA

Maximum current through Zener diode

I_{z max .} = \frac{10}{5} = 2 mA

And minimum current through Zener diode

\begin{matrix} I_{z min.} = 0 \\ ∴ I_{s max.} = 5 + 2 = 7 mA \end{matrix}

And

\mathrm{R}_{\mathrm{s} \text { min }}=\frac{\mathrm{V}_1}{\mathrm{I}_{\mathrm{s} \text { max }}}=\frac{3}{7} \mathrm{k} \Omega

Similarly

I_{s min .} = 5 mA

And

\mathrm{R}_{\mathrm{s} \text { max. }}=\frac{\mathrm{V}_1}{\mathrm{I}_{\mathrm{s} \text { min. }}}=\frac{3}{5} \mathrm{k} \Omega

∴ \frac{3}{7} k Ω < R_{s} < \frac{3}{5} k Ω

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