Verified Solution • 2025–26 Session moderate

QJEEM24Ph94a6: JEE Main 2024 Physics - Class 12 JEEM24Ph94a6 Solution: The energy equivalent of of substance is :

The energy equivalent of 1 g1 \mathrm{~g} of substance is :

Multiple Choice Options

  • A 5.6×1026 MeV5.6 \times 10^{26} \mathrm{~MeV}
  • B 5.6×1012 MeV5.6 \times 10^{12} \mathrm{~MeV}
  • C 5.6 eV5.6 \mathrm{~eV}
  • D 11.2×1024 MeV11.2 \times 10^{24} \mathrm{~MeV}

Step-by-Step Verified Solution

To determine the energy equivalent of a mass, we use Einstein's mass-energy equivalence principle given by the equation:

E=mc2E = mc^2

where:

- EE is the energy

- mm is the mass

- cc is the speed of light in a vacuum, which is approximately 3×108 m/s3 \times 10^8 \mathrm{~m/s}

Given the mass m=1 g=1×10−3 kgm = 1 \mathrm{~g} = 1 \times 10^{-3} \mathrm{~kg} , we can substitute these values into the equation:

E=(1×10−3 kg)×(3×108 m/s)2E = (1 \times 10^{-3} \mathrm{~kg}) \times (3 \times 10^8 \mathrm{~m/s})^2

Calculating this, we get:

E=1×10−3×9×1016E = 1 \times 10^{-3} \times 9 \times 10^{16}

E=9×1013 JE = 9 \times 10^{13} \mathrm{~J}

Next, to convert this energy into electron volts ( eV\mathrm{eV} ), we use the conversion factor: 1 J=6.242×1012 MeV1 \mathrm{~J} = 6.242 \times 10^{12} \mathrm{~MeV} .

Therefore:

E=9×1013 J×6.242×1012 MeV/JE = 9 \times 10^{13} \mathrm{~J} \times 6.242 \times 10^{12} \mathrm{~MeV/J}

Calculating this, we get:

E=5.6178×1026 MeVE = 5.6178 \times 10^{26} \mathrm{~MeV}

Therefore, the energy equivalent of 1 g1 \mathrm{~g} of a substance is:

Option A: 5.6×1026 MeV5.6 \times 10^{26} \mathrm{~MeV}

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