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QJEEM24Ph90e7: JEE Main 2024 Physics - Class 12 JEEM24Ph90e7 Solution: In the given figure an ammeter A consists of a coil connected…

In the given figure an ammeter A consists of a 240Ω240 \Omega coil connected in parallel to a 10Ω10 \Omega shunt. The reading of the ammeter is ________ mA\mathrm{mA} .

JEE Main 2024 (Online) 6th April Evening Shift Physics - Current Electricity Question 14 English

Step-by-Step Verified Solution

amp;i=24140⋅4+rA=24140⋅4+9⋅6=0.16 Aamp;i=160 mA\begin{aligned}& i=\frac{24}{140 \cdot 4+r_A}=\frac{24}{140 \cdot 4+9 \cdot 6}=0.16 \mathrm{~A} \\& i=160 \mathrm{~mA}\end{aligned}

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