QJEEM24Ph8bde: JEE Main 2024 Physics - Class 12 JEEM24Ph8bde Solution: The truth table of the given circuit diagram is :

Question

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The truth table of the given circuit diagram is :

JEE Main 2024 (Online) 27th January Evening Shift Physics - Semiconductor Question 28 English

A https://ik.imagekit.io/novatra/photos/92fe92281bb3bdb0602283d818fdbdcc6d35b05808e66c6d39c128b11ed7d47e.webp
B https://ik.imagekit.io/novatra/photos/f2d6236f6aeeee94041d341fc2a436a46792e74b7bbba2d722a21bb394fc281c.webp
C https://ik.imagekit.io/novatra/photos/0f7dc47485657378a7ce4fa533a85dd0c9cfcc7c332abe84794f2b1278f7d547.webp
D https://ik.imagekit.io/novatra/photos/15cafb9539c5f29fa7dfcadf0028aef5485f6ec700185463325ab386cf339137.webp

Accepted Answer

JEE Main 2024 (Online) 27th January Evening Shift Physics - Semiconductor Question 28 English Explanation

$Y = A \cdot \overset{―}{B} + \overset{―}{A} \cdot B$

This is XOR GATE

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