QJEEM24Ph8ab5: JEE Main 2024 Physics - Class 12 JEEM24Ph8ab5 Solution: A Zener diode of breakdown voltage 10   V is used as a…

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QJEEM24Ph8ab5: JEE Main 2024 Physics - Class 12 JEEM24Ph8ab5 Solution: A Zener diode of breakdown voltage 10   V is used as a…

A Zener diode of breakdown voltage $10 V$ is used as a voltage regulator as shown in the figure. The current through the Zener diode is :

JEE Main 2024 (Online) 30th January Morning Shift Physics - Semiconductor Question 22 English

Multiple Choice Options

A 0
B 30 mA
C 20 mA
D 50 mA

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JEE Main 2024 (Online) 30th January Morning Shift Physics - Semiconductor Question 22 English Explanation

Zener is in breakdown region.

$\begin{aligned} I_{3} = \frac{10}{500} = \frac{1}{50} \\ I_{1} = \frac{10}{200} = \frac{1}{20} \\ I_{2} = I_{1} - I_{3} \\ I_{2} = (\frac{1}{20} - \frac{1}{50}) = (\frac{3}{100}) = 30 mA \end{aligned}$

QJEEM24Ph8ab5: JEE Main 2024 Physics - Class 12 JEEM24Ph8ab5 Solution: A Zener diode of breakdown voltage 10 &nbsp; V is used as a…

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QJEEM24Ph8ab5: JEE Main 2024 Physics - Class 12 JEEM24Ph8ab5 Solution: A Zener diode of breakdown voltage 10 V is used as a…