QJEEM24Ph888f: JEE Main 2024 Physics - Class 11 JEEM24Ph888f Solution: Two identical spheres each of mass 2   kg and radius 50…

Two identical spheres each of mass $$2\mathrm{kg}$$ and radius $$50\mathrm{cm}$$ are fixed at the ends of a light rod so that the separation between the centers is $$150\mathrm{cm}$$. Then, moment of inertia of the system about an axis perpendicular to the rod and passing through its middle point is $$\frac{x}{20}\mathrm{kg}{\mathrm{m}}^2$$, where the value of $$x$$ is ___________.