Verified Solution • 2025–26 Session moderate

QJEEM24Ph8295: JEE Main 2024 Physics - Class 12 JEEM24Ph8295 Solution: The diffraction pattern of a light of wavelength 400   nm…

The diffraction pattern of a light of wavelength 400 nm diffracting from a slit of width 0.2 mm is focused on the focal plane of a convex lens of focal length 100 cm. The width of the 1st  secondary maxima will be :

Multiple Choice Options

  • A 2 mm
  • B 0.2 mm
  • C 0.02 mm
  • D 2 cm

Step-by-Step Verified Solution

Width of 1st  secondary maxima =λa⋅D

Here

a=0.2×10−3 mλ=400×10−9 mD=100×10−2

Width of 1st  secondary maxima

=400×10−90.2×10−3×100×10−2=2 mm

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring