Verified Solution • 2025–26 Session moderate

QJEEM24Ph8094: JEE Main 2024 Physics - Class 12 JEEM24Ph8094 Solution: An AC voltage is applied to a series LCR circuit which drives a …

An AC voltage V=20sin⁡200πtV=20 \sin 200 \pi t is applied to a series LCR circuit which drives a current I=10sin⁡(200πt+π3)I=10 \sin \left(200 \pi t+\frac{\pi}{3}\right) . The average power dissipated is:

Multiple Choice Options

  • A 21.6 W
  • B 200 W
  • C 173.2 W
  • D 50 W

Step-by-Step Verified Solution

amp;lt;Pgt;=IVcos⁡ϕamp;=202×102×cos⁡60∘amp;=50 W\begin{aligned}& <\mathrm{P}>=\mathrm{IV} \cos \phi \\& =\frac{20}{\sqrt{2}} \times \frac{10}{\sqrt{2}} \times \cos 60^{\circ} \\& =50 \mathrm{~W}\end{aligned}

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