Verified Solution • 2025–26 Session moderate

QJEEM24Ph7a9b: JEE Main 2024 Physics - Class 12 JEEM24Ph7a9b Solution: A potential divider circuit is connected with a dc source of ,…

A potential divider circuit is connected with a dc source of 20 V20 \mathrm{~V} , a light emitting diode of glow in voltage 1.8 V1.8 \mathrm{~V} and a zener diode of breakdown voltage of 3.2 V3.2 \mathrm{~V} . The length (PR) of the resistive wire is 20 cm20 \mathrm{~cm} . The minimum length of PQ to just glow the LED is _________ cm\mathrm{cm} .

JEE Main 2024 (Online) 8th April Evening Shift Physics - Semiconductor Question 15 English

Step-by-Step Verified Solution

JEE Main 2024 (Online) 8th April Evening Shift Physics - Semiconductor Question 15 English Explanation

For minimum length of PQP Q ,

amp;Vdiodes =1.8+3.2=5 Vamp;∴IPQ=2020×5amp;=5 cmamp;\begin{aligned}& \mathrm{V}_{\text {diodes }}=1.8+3.2=5 \mathrm{~V} \\& \therefore \quad I_{P Q}=\frac{20}{20} \times 5 \\& =5 \mathrm{~cm} \\&\end{aligned}

Related Learning Resources & Exam Preparation