QJEEM24Ph789d: JEE Main 2024 Physics - Class 11 JEEM24Ph789d Solution: Given below are two statements : Statement I : When speed of…

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QJEEM24Ph789d: JEE Main 2024 Physics - Class 11 JEEM24Ph789d Solution: Given below are two statements : Statement I : When speed of…

Given below are two statements :

Statement I : When speed of liquid is zero everywhere, pressure difference at any two points depends on equation $P_{1} - P_{2} = ρ g (h_{2} - h_{1})$ .

Statement II : In ventury tube shown $2 gh = v_{1}^{2} - v_{2}^{2}$

JEE Main 2024 (Online) 4th April Morning Shift Physics - Properties of Matter Question 32 English

In the light of the above statements, choose the most appropriate answer from the options given below.

Multiple Choice Options

A Statement I is correct but Statement II is incorrect.
B Both Statement I and Statement II are correct.
C Both Statement I and Statement II are incorrect.
D Statement I is incorrect but Statement II is correct.

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Accepted Answer

If speed $= 0$

Then $P_{1} + ρ g h_{1} = P_{2} + ρ g h_{2}$

In given ventury tube,

$\begin{aligned} P_{1} + ρ g h + \frac{1}{2} ρ v_{1}^{2} = P_{2} + \frac{1}{2} ρ v_{2}^{2} \\ \Rightarrow \frac{1}{2} ρ (v_{1}^{2} - v_{2}^{2}) = (P_{2} - P_{1}) - ρ g h \\ \Rightarrow v_{1}^{2} - v_{2}^{2} = \frac{2 (P_{2} - P_{1})}{ρ} - 2 g h \end{aligned}$

QJEEM24Ph789d: JEE Main 2024 Physics - Class 11 JEEM24Ph789d Solution: Given below are two statements : Statement I : When speed of…

Multiple Choice Options

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