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QJEEM24Ph774b: JEE Main 2024 Physics - Class 12 JEEM24Ph774b Solution: In Young's double slit experiment, carried out with light of…

In Young's double slit experiment, carried out with light of wavelength 5000 Ao5000~\mathop A\limits^o , the distance between the slits is 0.3 mm0.3 \mathrm{~mm} and the screen is at 200 cm200 \mathrm{~cm} from the slits. The central maximum is at x=0 cmx=0 \mathrm{~cm} . The value of xx for third maxima is __________ mm\mathrm{mm} .

Step-by-Step Verified Solution

xamp;=3λDdamp;=3×5000×10−10×200×10−20.3×10−3amp;=10 mm\begin{aligned}x & =\frac{3 \lambda D}{d} \\& =\frac{3 \times 5000 \times 10^{-10} \times 200 \times 10^{-2}}{0.3 \times 10^{-3}} \\& =10 \mathrm{~mm}\end{aligned}

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