QJEEM24Ph760a: JEE Main 2024 Physics - Class 11 JEEM24Ph760a Solution: Time periods of oscillation of the same simple pendulum…

To find the arithmetic mean of the time periods recorded, we need to sum up the values and then divide by the number of readings. Let's calculate the sum first:

$$4.62\mathrm{s}+4.632\mathrm{s}+4.6\mathrm{s}+4.64\mathrm{s}$$

Adding these values together:

$$4.62+4.632+4.6+4.64=18.492\mathrm{s}$$

Now, we divide this sum by the number of readings, which is 4:

$$\frac{18.492\mathrm{s}}{4}=4.623\mathrm{s}$$

So, the arithmetic mean of these readings is $$4.623\mathrm{s}$$. However, we need to consider the significant figures. The least number of significant figures among the readings is 2 (from 4.6 s). Hence, the mean should also be represented with 2 significant figures.

In this case, the correct answer with proper significant figures is:

Option B

4.6 s