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QJEEM24Ph6d9b: JEE Main 2024 Physics - Class 12 JEEM24Ph6d9b Solution: A square loop of side 15   cm being moved towards right at …

A square loop of side 15 cm being moved towards right at a constant speed of 2 cm/s as shown in figure. The front edge enters the 50 cm wide magnetic field at t=0. The value of induced emf in the loop at t=10 s will be :

JEE Main 2024 (Online) 9th April Evening Shift Physics - Electromagnetic Induction Question 11 English

Multiple Choice Options

  • A zero
  • B 4.5 mV
  • C 0.3 mV
  • D 3 mV

Step-by-Step Verified Solution

Time taken to cross the field region

=502=25 s

At 10 s the loop is inside field and flux is not changing.

∴εinduced =0

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