Verified Solution • 2025–26 Session moderate

QJEEM24Ph6cad: JEE Main 2024 Physics - Class 11 JEEM24Ph6cad Solution: The resistance R = V I where V = ( 200 ± 5 ) V and I = ( 20 ±…

The resistance $R = \frac{V}{I}$ where $V = (200 \pm 5) V$ and $I = (20 \pm 0.2) A$ , the percentage error in the measurement of $R$ is :

Multiple Choice Options

A 5.50%
B 3%
C 7%
D 3.50%

Step-by-Step Verified Solution

$R = \frac{V}{1}$

According to error analysis

$\begin{aligned} \frac{dR}{R} = \frac{dV}{V} + \frac{dI}{I} \\ \frac{dR}{R} = \frac{5}{200} + \frac{0.2}{20} \\ \frac{dR}{R} = \frac{7}{200} \\ % error \frac{dR}{R} \times 100 = \frac{7}{200} \times 100 = 3.5 % \end{aligned}$

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