QJEEM24Ph5c7f: JEE Main 2024 Physics - Class 12 JEEM24Ph5c7f Solution: A convex mirror of radius of curvature forms an image that is…

Given $\mathrm{R}=30 \mathrm{~cm}$

$\mathrm{f}=\mathrm{R} / 2=+15 \mathrm{~cm}$

Magnification $(\mathrm{m})= \pm \frac{1}{2}$

For convex mirror, virtual image is formed for real object.

Therefore, $\mathrm{m}$ is +ve

$\begin{aligned}& \frac{1}{2}=\frac{f}{f-u} \\& u=-15 \mathrm{~cm}\end{aligned}$