Verified Solution • 2025–26 Session moderate

QJEEM24Ph5a39: JEE Main 2024 Physics - Class 11 JEEM24Ph5a39 Solution: The specific heat at constant pressure of a real gas obeying…

The specific heat at constant pressure of a real gas obeying PV2=RTP V^2=R T equation is:

Multiple Choice Options

  • A R
  • B CV+RC_V+R
  • C CV+R2VC_V+\frac{R}{2 V}
  • D R3+CV\frac{R}{3}+C_V

Step-by-Step Verified Solution

amp;∵PV2=RTamp;P(2vdv)+V2(dP)=RdT\begin{aligned}& \because \quad P V^2=R T \\& P(2 v d v)+V^2(d P)=R d T\end{aligned}

at P=P= const.

Pdv=RdT2V... (i)P d v=\frac{R d T}{2 V} \quad \text{... (i)}

Now, for n=1n=1

amp;dθ=dv+dwamp;CPdT=CvdT+Pdv... (ii)\begin{aligned}& d \theta=d v+d w \\& C_P d T=C_v d T+P d v \quad \text{... (ii)}\end{aligned}

from (i) and (ii)

CP=CV+R2VC_P=C_V+\frac{R}{2 V}

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