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QJEEM24Ph58f6: JEE Main 2024 Physics - Class 12 JEEM24Ph58f6 Solution: Given below are two statements : Statement I : Figure shows the …

Given below are two statements :

JEE Main 2024 (Online) 5th April Morning Shift Physics - Dual Nature of Radiation Question 19 English

Statement I : Figure shows the variation of stopping potential with frequency (v) for the two photosensitive materials M1 and M2. The slope gives value of he, where h is Planck's constant, e is the charge of electron.

Statement II : M2 will emit photoelectrons of greater kinetic energy for the incident radiation having same frequency.

In the light of the above statements, choose the most appropriate answer from the options given below.

Multiple Choice Options

  • A Statement I is correct and Statement II is incorrect
  • B Statement I is incorrect but Statement II is correct
  • C Both Statement I and Statement II are correct
  • D Both Statement I and Statement II are incorrect

Step-by-Step Verified Solution

V0=hef−hef0⇒ Slope =he (S-I is correct) ∵(f0)1<(f0)2∴(S−II is incorrect) ∴ Option (3) is correct. 

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