Verified Solution • 2025–26 Session moderate

QJEEM24Ph5258: JEE Main 2024 Physics - Class 11 JEEM24Ph5258 Solution: The equation of state of a real gas is given by , where and are …

The equation of state of a real gas is given by (P+aV2)(V−b)=RT\left(\mathrm{P}+\frac{\mathrm{a}}{\mathrm{V}^2}\right)(\mathrm{V}-\mathrm{b})=\mathrm{RT} , where P,V\mathrm{P}, \mathrm{V} and T\mathrm{T} are pressure, volume and temperature respectively and R\mathrm{R} is the universal gas constant. The dimensions of ab2\frac{\mathrm{a}}{\mathrm{b}^2} is similar to that of :

Multiple Choice Options

  • A P
  • B RT
  • C PV
  • D R

Step-by-Step Verified Solution

amp;[P]=[aV2]⇒[a]=[PV2]amp; And [V]=[b]amp;[a][b2]=[PV2][V2]=[P]\begin{aligned}& {[\mathrm{P}]=\left[\frac{\mathrm{a}}{\mathrm{V}^2}\right] \Rightarrow[\mathrm{a}]=\left[\mathrm{PV}^2\right]} \\& \text { And }[\mathrm{V}]=[\mathrm{b}] \\& \frac{[\mathrm{a}]}{\left[\mathrm{b}^2\right]}=\frac{\left[\mathrm{PV}^2\right]}{\left[\mathrm{V}^2\right]}=[\mathrm{P}]\end{aligned}

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring