Verified Solution • 2025–26 Session moderate

QJEEM24Ph51a4: JEE Main 2024 Physics - Class 12 JEEM24Ph51a4 Solution: A plane electromagnetic wave propagating in -direction is…

A plane electromagnetic wave propagating in x\mathrm{x} -direction is described by

Ey=(200Vm−1)sin⁡[1.5×107t−0.05x]; E_y=\left(200 \mathrm{Vm}^{-1}\right) \sin \left[1.5 \times 10^7 t-0.05 x\right] \text {; }

The intensity of the wave is :

(Use ϵ0=8.85×10−12C2 N−1 m−2\epsilon_0=8.85 \times 10^{-12} \mathrm{C}^2 \mathrm{~N}^{-1} \mathrm{~m}^{-2} )

Multiple Choice Options

  • A 35.4 Wm−235.4 \mathrm{~Wm}^{-2}
  • B 53.1 Wm−253.1 \mathrm{~Wm}^{-2}
  • C 26.6 Wm−226.6 \mathrm{~Wm}^{-2}
  • D 106.2 Wm−2106.2 \mathrm{~Wm}^{-2}

Step-by-Step Verified Solution

amp;I=12ε0E02×camp;I=12×8.85×10−12×4×104×3×108amp;I=53.1 W/m2\begin{aligned}& \mathrm{I}=\frac{1}{2} \varepsilon_0 \mathrm{E}_0^2 \times \mathrm{c} \\& \mathrm{I}=\frac{1}{2} \times 8.85 \times 10^{-12} \times 4 \times 10^4 \times 3 \times 10^8 \\& \mathrm{I}=53.1 \mathrm{~W} / \mathrm{m}^2\end{aligned}

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