Verified Solution • 2025–26 Session moderate

QJEEM24Ph4ef6: JEE Main 2024 Physics - Class 12 JEEM24Ph4ef6 Solution: A nucleus has mass number and volume . Another nucleus has mass …

A nucleus has mass number A1A_1 and volume V1V_1 . Another nucleus has mass number A2A_2 and Volume V2V_2 . If relation between mass number is A2=4A1A_2=4 A_1 , then V2V1=\frac{V_2}{V_1}= __________.

Step-by-Step Verified Solution

For a nucleus

Volume: V=43πR3\mathrm{V}=\frac{4}{3} \pi \mathrm{R}^3

amp;R=R0(A)1/3amp; V=43πR03Aamp;⇒V2 V1=A2 A1=4\begin{aligned}& \mathrm{R}=\mathrm{R}_0(\mathrm{A})^{1 / 3} \\& \mathrm{~V}=\frac{4}{3} \pi \mathrm{R}_0^3 \mathrm{A} \\& \Rightarrow \frac{\mathrm{V}_2}{\mathrm{~V}_1}=\frac{\mathrm{A}_2}{\mathrm{~A}_1}=4\end{aligned}

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