Verified Solution • 2025–26 Session moderate

QJEEM24Ph4db4: JEE Main 2024 Physics - Class 12 JEEM24Ph4db4 Solution: Match List I with List II .tg…

Match List I with List II

LIST I LIST II
A. Purely capacitive circuit I. JEE Main 2024 (Online) 4th April Evening Shift Physics - Alternating Current Question 13 English 1
B. Purely inductive circuit II. JEE Main 2024 (Online) 4th April Evening Shift Physics - Alternating Current Question 13 English 2
C. LCR series at resonance III. JEE Main 2024 (Online) 4th April Evening Shift Physics - Alternating Current Question 13 English 3
D. LCR series circuit IV. JEE Main 2024 (Online) 4th April Evening Shift Physics - Alternating Current Question 13 English 4

Choose the correct answer from the options given below:

Multiple Choice Options

  • A A-IV. B-I, C-III, D-II
  • B A-I. B-IV, C-II, D-III
  • C A-IV. B-I, C-II, D-III
  • D A-I. B-IV, C-III, D-II

Step-by-Step Verified Solution

For pure capacitive circuit, II lead by 90∘90^{\circ} to V\mathrm{V}

For pure inductive circuit, VV lead by 90∘90^{\circ} to II

At series LCR resonance, II and VV are in same phase.

For LCR series circuit, VV and I may suffer some phase difference.

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