Verified Solution • 2025–26 Session moderate

QJEEM24Ph4c4c: JEE Main 2024 Physics - Class 11 JEEM24Ph4c4c Solution: Match List I with List II .tg…

Match List I with List II

LIST I LIST II
A. Torque I. [M1L1T−2A−2]
B. Magnetic field II. [L2A1]
C. Magnetic moment III. [M1T−2A−1]
D. Permeability of free space IV. [M1L2T−2]

Choose the correct answer from the options given below:

Multiple Choice Options

  • A A-I, B-III, C-II, D-IV
  • B A-IV, B-II, C-III, D-I
  • C A-III, B-I, C-II, D-IV
  • D A-IV, B-III, C-II, D-I

Step-by-Step Verified Solution

To determine the correct matches between List I and List II, we need to consider the dimensional formulas of the given physical quantities.

  1. Torque (τ) is defined as the product of force (F) and distance (d):

τ=F⋅d\tau = F \cdot d

The dimensional formula for torque is:

[τ]=[M1L2T−2][\tau] = [M^1 L^2 T^{-2}]

Thus, Torque corresponds to IV.

  1. Magnetic field (B) is derived from the relation involving force (F), charge (q), and velocity (V):

F=qVBF = qVB

The dimensional formula for the magnetic field is:

[B]=[M1T−2A−1][B] = [M^1 T^{-2} A^{-1}]

Thus, Magnetic field corresponds to III.

  1. Magnetic moment (M) is the product of current (I) and area (A):

M=I⋅AM = I \cdot A

The dimensional formula for the magnetic moment is:

[M]=[L2A1][M] = [L^2 A^1]

Thus, Magnetic moment corresponds to II.

  1. Permeability of free space (μ₀) has the dimensional formula:

[μ0]=[M1L1T−2A−2][μ₀] = [M^1 L^1 T^{-2} A^{-2}]

Thus, Permeability of free space corresponds to I.

Based on the above analysis, the correct matches are:

  • A. Torque – IV

  • B. Magnetic Field – III

  • C. Magnetic Moment – II

  • D. Permeability of free space – I

Therefore, the correct option is Option D:

A-IV, B-III, C-II, D-I.

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