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QJEEM24Ph462d: JEE Main 2024 Physics - Class 12 JEEM24Ph462d Solution: A parallel beam of monochromatic light of wavelength 5000 is…

A parallel beam of monochromatic light of wavelength 5000 Ao\mathop A\limits^o is incident normally on a single narrow slit of width 0.001 mm0.001 \mathrm{~mm} . The light is focused by convex lens on screen, placed on its focal plane. The first minima will be formed for the angle of diffraction of _________ (degree).

Step-by-Step Verified Solution

For first minima

amp;asin⁡θ=λamp;⇒sin⁡θ=λa=5000×10−101×10−6=12amp;⇒θ=30∘\begin{aligned}& \operatorname{asin} \theta=\lambda \\& \Rightarrow \sin \theta=\frac{\lambda}{a}=\frac{5000 \times 10^{-10}}{1 \times 10^{-6}}=\frac{1}{2} \\& \Rightarrow \theta=30^{\circ}\end{aligned}

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