Verified Solution • 2025–26 Session moderate

QJEEM24Ph4487: JEE Main 2024 Physics - Class 12 JEEM24Ph4487 Solution: Two sources of light emit with a power of . The ratio of number …

Two sources of light emit with a power of 200 W200 \mathrm{~W} . The ratio of number of photons of visible light emitted by each source having wavelengths 300 nm300 \mathrm{~nm} and 500 nm500 \mathrm{~nm} respectively, will be :

Multiple Choice Options

  • A 5:35: 3
  • B 3:53: 5
  • C 1:51: 5
  • D 1:31: 3

Step-by-Step Verified Solution

amp;n1×hcλ1=200amp;n2×hcλ2=200amp;n1n2=λ1λ2=300500amp;n1n2=35\begin{aligned}& \mathrm{n}_1 \times \frac{\mathrm{hc}}{\lambda_1}=200 \\& \mathrm{n}_2 \times \frac{\mathrm{hc}}{\lambda_2}=200 \\& \frac{\mathrm{n}_1}{\mathrm{n}_2}=\frac{\lambda_1}{\lambda_2}=\frac{300}{500} \\& \frac{\mathrm{n}_1}{\mathrm{n}_2}=\frac{3}{5}\end{aligned}

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