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QJEEM24Ph3fd4: JEE Main 2024 Physics - Class 12 JEEM24Ph3fd4 Solution: The magnetic flux (in weber) linked with a closed circuit of…

The magnetic flux ϕ\phi (in weber) linked with a closed circuit of resistance 8Ω8 \Omega varies with time (in seconds) as ϕ=5t2−36t+1\phi=5 t^2-36 t+1 . The induced current in the circuit at t=2 st=2 \mathrm{~s} is __________ A.

Step-by-Step Verified Solution

amp;ε=−(dϕdt)=10t−36amp; at t=2,ε=16 Vamp;i=εR=168=2 A\begin{aligned}& \varepsilon=-\left(\frac{\mathrm{d} \phi}{\mathrm{dt}}\right)=10 \mathrm{t}-36 \\& \text { at } \mathrm{t}=2, \varepsilon=16 \mathrm{~V} \\& \mathrm{i}=\frac{\varepsilon}{\mathrm{R}}=\frac{16}{8}=2 \mathrm{~A}\end{aligned}

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