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QJEEM24Ph2fb1: JEE Main 2024 Physics - Class 12 JEEM24Ph2fb1 Solution: The equivalent resistance between A and B is :

The equivalent resistance between A and B is :

JEE Main 2024 (Online) 9th April Morning Shift Physics - Current Electricity Question 30 English

Multiple Choice Options

  • A 18 Ω
  • B 27 Ω
  • C 19 Ω
  • D 25 Ω

Step-by-Step Verified Solution

Redrawing the circuit

JEE Main 2024 (Online) 9th April Morning Shift Physics - Current Electricity Question 30 English Explanation

⇒Req=6+5+8=19Ω

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