Verified Solution • 2025–26 Session moderate

QJEEM24Ph2c60: JEE Main 2024 Physics - Class 11 JEEM24Ph2c60 Solution: A train is moving with a speed of on rails which are apart. To…

A train is moving with a speed of 12 m/s12 \mathrm{~m} / \mathrm{s} on rails which are 1.5 m1.5 \mathrm{~m} apart. To negotiate a curve radius 400 m400 \mathrm{~m} , the height by which the outer rail should be raised with respect to the inner rail is (Given, g=10 m/s2)g=10 \mathrm{~m} / \mathrm{s}^2) :

Multiple Choice Options

  • A 6.0 cm
  • B 5.4 cm
  • C 4.8 cm
  • D 4.2 cm

Step-by-Step Verified Solution

tan⁡θ=v2Rg=12×1210×400\tan \theta=\frac{v^2}{R g}=\frac{12 \times 12}{10 \times 400}

JEE Main 2024 (Online) 27th January Morning Shift Physics - Circular Motion Question 15 English Explanation

amp;tan⁡θ=h1.5amp;⇒h1.5=1444000amp; h=5.4 cm\begin{aligned}& \tan \theta=\frac{\mathrm{h}}{1.5} \\\\& \Rightarrow \frac{\mathrm{h}}{1.5}=\frac{144}{4000} \\\\& \mathrm{~h}=5.4 \mathrm{~cm}\end{aligned}

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