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QJEEM24Ph2560: JEE Main 2024 Physics - Class 11 JEEM24Ph2560 Solution: A block of mass 5   kg is placed on a rough inclined…

JEE Main 2024 (Online) 31st January Evening Shift Physics - Laws of Motion Question 20 English

A block of mass 5 kg is placed on a rough inclined surface as shown in the figure. If F1→ is the force required to just move the block up the inclined plane and F2→ is the force required to just prevent the block from sliding down, then the value of |F1→|−|F2→| is : [Use g=10 m/s2]

Multiple Choice Options

  • A 53N
  • B 532N
  • C 10 N
  • D 253N

Step-by-Step Verified Solution

fK=μmgcos⁡θ=0.1×50×32=2.53 N

JEE Main 2024 (Online) 31st January Evening Shift Physics - Laws of Motion Question 20 English Explanation 1

F1=mgsin⁡θ+fK=25+2.53

JEE Main 2024 (Online) 31st January Evening Shift Physics - Laws of Motion Question 20 English Explanation 2

F2=mgsin⁡θ−fK=25−2.53∴F1−F2=53 N

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