Verified Solution • 2025–26 Session moderate

QJEEM24Ph24c1: JEE Main 2024 Physics - Class 11 JEEM24Ph24c1 Solution: A closed organ pipe long gives 7 beats per second with an open…

A closed organ pipe 150 cm150 \mathrm{~cm} long gives 7 beats per second with an open organ pipe of length 350 cm350 \mathrm{~cm} , both vibrating in fundamental mode. The velocity of sound is __________ m/s\mathrm{m} / \mathrm{s} .

Step-by-Step Verified Solution

JEE Main 2024 (Online) 27th January Evening Shift Physics - Waves Question 11 English Explanation

amp;fc=v4ℓ1fo=v2ℓ2amp;∣fc−f0∣=7amp;v4×150−v2×350=7amp;v600 cm−v700 cm=7amp;v6 m−v7 m=7amp;v(142)=7amp;v=42×7amp;=294 m/s\begin{aligned}& \mathrm{f}_{\mathrm{c}}=\frac{\mathrm{v}}{4 \ell_1} \quad \mathrm{f}_{\mathrm{o}}=\frac{\mathrm{v}}{2 \ell_2} \\& \left|\mathrm{f}_{\mathrm{c}}-\mathrm{f}_0\right|=7 \\& \frac{\mathrm{v}}{4 \times 150}-\frac{\mathrm{v}}{2 \times 350}=7 \\& \frac{\mathrm{v}}{600 \mathrm{~cm}}-\frac{\mathrm{v}}{700 \mathrm{~cm}}=7 \\& \frac{\mathrm{v}}{6 \mathrm{~m}}-\frac{\mathrm{v}}{7 \mathrm{~m}}=7 \\& \mathrm{v}\left(\frac{1}{42}\right)=7 \\& \mathrm{v}=42 \times 7 \\& =294 \mathrm{~m} / \mathrm{s}\end{aligned}

Related Learning Resources & Exam Preparation