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QJEEM24Ph22bc: JEE Main 2024 Physics - Class 12 JEEM24Ph22bc Solution: A square loop of side 10   cm and resistance 0.7 Ω is…

A square loop of side 10 cm and resistance 0.7Ω is placed vertically in east-west plane. A uniform magnetic field of 0.20T is set up across the plane in north east direction. The magnetic field is decreased to zero in 1 s at a steady rate. Then, magnitude of induced emf is x×10−3 V. The value of x is __________.

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JEE Main 2024 (Online) 29th January Morning Shift Physics - Electromagnetic Induction Question 15 English Explanation

A→=(0.1)2j^B→=0.22i^+0.22j^

Magnitude of induced emf

e=ΔϕΔt=B→⋅A→−01=2×10−3 V

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