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QJEEM24Ph2061: JEE Main 2024 Physics - Class 12 JEEM24Ph2061 Solution: The current of flows in a square loop of sides is placed in…

The current of 5 A5 \mathrm{~A} flows in a square loop of sides 1 m1 \mathrm{~m} is placed in air. The magnetic field at the centre of the loop is X2×10−7TX \sqrt{2} \times 10^{-7} T . The value of XX is _________.

Step-by-Step Verified Solution

amp;B=4×μ0i4π(1/2)(12+12)amp;=4×10−7×5×2×2amp;−402×10−7 T\begin{aligned}& \mathrm{B}=4 \times \frac{\mu_0 \mathrm{i}}{4 \pi(1 / 2)}\left(\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}\right) \\& =4 \times 10^{-7} \times 5 \times 2 \times \sqrt{2} \\& -40 \sqrt{2} \times 10^{-7} \mathrm{~T}\end{aligned}

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