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QJEEM24Ph160d: JEE Main 2024 Physics - Class 12 JEEM24Ph160d Solution: In the experiment to determine the galvanometer resistance by…

In the experiment to determine the galvanometer resistance by half-deflection method, the plot of 1/θ1 / \theta vs the resistance (R) of the resistance box is shown in the figure. The figure of merit of the galvanometer is _________ ×10−1 A/\times 10^{-1} \mathrm{~A} / division. [The source has emf 2 V2 \mathrm{~V} ]

JEE Main 2024 (Online) 5th April Morning Shift Physics - Current Electricity Question 20 English

Step-by-Step Verified Solution

13 A⟶12div\frac{1}{3} \mathrm{~A} \longrightarrow \frac{1}{2} \mathrm{div}

12 A⟶23div\frac{1}{2} \mathrm{~A} \longrightarrow \frac{2}{3} \mathrm{div}

 Figure of merit =ΔiΔθamp;12−−23−12amp;=0.5amp;=5×10−1 A/div\text { Figure of merit }=\frac{\Delta i}{\Delta \theta} \quad \begin{aligned}& \frac{\frac{1}{2}--}{\frac{2}{3}-\frac{1}{2}} \\&=0.5 \\&=5 \times 10^{-1} \mathrm{~A} / \mathrm{div}\end{aligned}

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