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QJEEM24Ph1529: JEE Main 2024 Physics - Class 12 JEEM24Ph1529 Solution: A uniform magnetic field of 2 × 10 − 3   T acts along…

A uniform magnetic field of 2×10−3 T acts along positive Y-direction. A rectangular loop of sides 20 cm and 10 cm with current of 5 A is in Y−Z plane. The current is in anticlockwise sense with reference to negative X axis. Magnitude and direction of the torque is:

Multiple Choice Options

  • A 2×10−4 N- m along negative Z-direction
  • B 2×10−4 N - m along positive X-direction
  • C 2×10−4 N - m along positive Y-direction
  • D 2×10−4 N - m along positive Z-direction

Step-by-Step Verified Solution

JEE Main 2024 (Online) 31st January Evening Shift Physics - Magnetic Effect of Current Question 37 English Explanation

M→=iA→=5×(0.2)×(0.1)(−i^)=0.1(−i^)τ→=M→×B→=0.1(−i^)×(2×10−3)(j^)=2×10−4(−k^)N−m

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