Verified Solution • 2025–26 Session moderate

QJEEM24Ph14bb: JEE Main 2024 Physics - Class 12 JEEM24Ph14bb Solution: A coil is places perpendicular to a magnetic field of 5000…

A coil is places perpendicular to a magnetic field of 5000 T. When the field is changed to 3000 T in 2 s, an induced emf of 22 V is produced in the coil. If the diameter of the coil is 0.02 m, then the number of turns in the coil is:

Multiple Choice Options

  • A 35
  • B 70
  • C 7
  • D 140

Step-by-Step Verified Solution

ε=N(Δϕt)Δϕ=(ΔB)ABi=5000 T, Bf=3000 T d=0.02 mr=0.01 mΔϕ=(ΔB)A=(2000)π(0.01)2=0.2πε=N(Δϕt)⇒22=N(0.2π2)N=70

Related Learning Resources & Exam Preparation