Verified Solution • 2025–26 Session moderate

QJEEM24Ph1451: JEE Main 2024 Physics - Class 12 JEEM24Ph1451 Solution: Match List I with List II: .tg…

Match List I with List II:

	LIST I (Y vs X)		LIST II (Shape of Graph)
A.	Y-magnetic susceptibility X = magnetising field	I.
B.	Y = magnetic field X = distance from centre of a current carrying wire for x < a (where a = radius of wire)	II.
C.	Y = magnetic field $X =$ distance from centre of a current carrying wire for $x > a$ (where $a =$ radius of wire)	III.
D.	Y = magnetic field inside solenoid X = distance from centre	IV.

Choose the correct answer from the options given below :

Multiple Choice Options

A (A)-(III), (B)-(IV), (C)- (I), (D)-(II)
B (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
C (A)-(IV), (B)-(I), (C)-(III), (D)-(II)
D (A)-(I), (B)-(III), (C)-(II), (D)-(IV)

Step-by-Step Verified Solution

In para and dia materials, susceptibility is independent of magnetic field.

Inside a current carrying wire, $B \propto X$

Outside a current carrying wire, $B \propto \frac{1}{x}$

Inside a solenoid, B is constant upto ends.

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