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QJEEM24Ph11f8: JEE Main 2024 Physics - Class 12 JEEM24Ph11f8 Solution: Two slits are 1   mm apart and the screen is located 1…

Two slits are 1 mm apart and the screen is located 1 m away from the slits. A light of wavelength 500 nm is used. The width of each slit to obtain 10 maxima of the double slit pattern within the central maximum of the single slit pattern is __________ ×10−4 m.

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JEE Main 2024 (Online) 8th April Evening Shift Physics - Wave Optics Question 17 English Explanation

 Width central maxima =10 fringe width =2λθa=10β2λθa=10×λDda=d5=10−35=2×10−4

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